Quicker Maths
20Jul/095

A painter needed three days to paint the walls of a room

A painter needed three days tp paint the walls of a room. How long would it take him, working at the same rate, to paint a room twice as long, twice as wide, and twice as high?

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  1. surface area of wall=2ab+2bc+2ca.since everything is doubled now new surface area=2*2a*2b+2*2b*2c+2*2c*2a.i.e 4 times of tne existing one.hence days required=4*3= 12 days

  2. Vittal….sorry friend your are wrong.Right answer has been given by Mohit and he also explained it.Better luck next time.

  3. Hey Mohit…congratulations….you got it right.

  4. Room 1 Surface area: 2 (LXH + WXH)
    Room 2 Surface area: 2 (2LX2H +2WX2H)

    Answer is 3 X 4 = 12 days


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