A painter needed three days tp paint the walls of a room. How long would it take him, working at the same rate, to paint a room twice as long, twice as wide, and twice as high?
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June 15th, 2010 - 08:41
surface area of wall=2ab+2bc+2ca.since everything is doubled now new surface area=2*2a*2b+2*2b*2c+2*2c*2a.i.e 4 times of tne existing one.hence days required=4*3= 12 days
August 3rd, 2009 - 11:30
Vittal….sorry friend your are wrong.Right answer has been given by Mohit and he also explained it.Better luck next time.
August 2nd, 2009 - 07:12
48 days
July 27th, 2009 - 11:37
Hey Mohit…congratulations….you got it right.
July 25th, 2009 - 11:56
Room 1 Surface area: 2 (LXH + WXH)
Room 2 Surface area: 2 (2LX2H +2WX2H)
Answer is 3 X 4 = 12 days