# A Problem of Candy Bars

Recently I attended a birthday party. All the

children in the party were having candy bars. All the children got three candy bars each except the child sitting in the end. She got only two candy bars. If only each child had been given two candy bars there would have been eight candy bars remaining. How many candy bars were there altogether to begin with?

#### Vineet Patawari

Hi, I'm Vineet Patawari. I fell in love with numbers after being scared of them for quite some time. Now, I'm here to make you feel comfortable with numbers and help you get rid of Math Phobia!

## 5 thoughts to “A Problem of Candy Bars”

1. Okay, that’s a good start however i’m going to consider that a great deal more. Will let you know just what more i have found.

2. 3*x+2*1=2*(x+1)+8=total candy bars //x is the count of child less by 1
x=8
candy bar=26

3. anish says:

Let x, y be the no. of candy bars and no. of children respectively.

According to first statement, y=3(x-1) +2*1
According to second statement, y=2*x + 8

Combining both statements, we, get x = 9. Hence, no. of candies, y = 26.

4. akrati says:

hey mohit can u tell me how u did this

5. mohit says:

26 candy bars