8Dec/095
A Problem of Candy Bars
Recently I attended a birthday party. All the
children in the party were having candy bars. All the children got three candy bars each except the child sitting in the end. She got only two candy bars. If only each child had been given two candy bars there would have been eight candy bars remaining. How many candy bars were there altogether to begin with?
You may also like:
Who is behind QuickerMaths?
I am Vineet Patawari - PGDM (IIM Indore), ACA, B.Com(H). My passion for Mathematics, specially Vedic Maths encouraged me to start QuickerMaths
I believe that if trained properly using powerful tools like Vedic Maths, the immense intellect of human mind can be ignited instantly - find out more
Get Maths Tricks by Email
Recent Comments
A, B and C can do a piece of work in 40, 60 and 120... – 07Feb12
as a night watchman he is not supposed to sleep during the night . as... – 06Feb12
ramlal is a night watchman and he is sleep on duty therefor boss fire him,... – 06Feb12
Dear, It is good..... But I was already given this question on 06-12-2011 at 11.08... – 05Feb12
he rewarded the watchman because watchman saved his life by warning him that the plane... – 05Feb12
Most Popular
- 100% Finding Cube Root – Vedic Maths Way
- 67% Shortcut to Find Square of a Number
- 57% Shortcut Method for Multiplication
- 56% Shortcut to find the Cube of a number
- 53% Squaring any 2-digit number
- 49% Divisibility Rule of 7, 13, 17, 19, 23, 29, 31, 37, 41, 43 and 47
- 45% Division in Vedic Mathematics
- 45% Herons Method of Finding Roots
- 43% You can make a difference
- 41% Quicker Maths by M Tyra
- 40% Quick calculations for extremely large numbers
- 39% Divisibility Rules for 7 , 11 and 13
- 37% How to convert from decimal to other number systems
- 36% Quick Multiplication up to 20 x 20
- 35% Logical Reasoning Books
May 9th, 2011 - 11:44
Okay, that’s a good start however i’m going to consider that a great deal more. Will let you know just what more i have found.
December 10th, 2009 - 18:01
3*x+2*1=2*(x+1)+8=total candy bars //x is the count of child less by 1
x=8
candy bar=26
December 10th, 2009 - 10:05
Let x, y be the no. of candy bars and no. of children respectively.
According to first statement, y=3(x-1) +2*1
According to second statement, y=2*x + 8
Combining both statements, we, get x = 9. Hence, no. of candies, y = 26.
December 9th, 2009 - 17:57
hey mohit can u tell me how u did this
December 8th, 2009 - 23:10
26 candy bars