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	<title>Comments on: Birthday Paradox</title>
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	<link>http://www.quickermaths.com/birthday-paradox/</link>
	<description>Vedic Maths Tricks &#124; Puzzles, Brainteasers &#38; Riddles</description>
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	<item>
		<title>By: Pratik Gupta</title>
		<link>http://www.quickermaths.com/birthday-paradox/comment-page-1/#comment-1294</link>
		<dc:creator>Pratik Gupta</dc:creator>
		<pubDate>Mon, 23 Aug 2010 18:59:19 +0000</pubDate>
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		<description>please email all the above question&#039;s answers @ my email...I willl be grateful 2 u...</description>
		<content:encoded><![CDATA[<p>please email all the above question&#8217;s answers @ my email&#8230;I willl be grateful 2 u&#8230;</p>
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	<item>
		<title>By: mohit</title>
		<link>http://www.quickermaths.com/birthday-paradox/comment-page-1/#comment-380</link>
		<dc:creator>mohit</dc:creator>
		<pubDate>Fri, 13 Nov 2009 19:18:37 +0000</pubDate>
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		<description>1.  (1/365)^22       as,  365*1^22 / 365^23

2.  (1/365)^56        as, 365*1^56 / 365^57

3.  when there are atleast 366 people</description>
		<content:encoded><![CDATA[<p>1.  (1/365)^22       as,  365*1^22 / 365^23</p>
<p>2.  (1/365)^56        as, 365*1^56 / 365^57</p>
<p>3.  when there are atleast 366 people</p>
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	<item>
		<title>By: Vedic Maths</title>
		<link>http://www.quickermaths.com/birthday-paradox/comment-page-1/#comment-351</link>
		<dc:creator>Vedic Maths</dc:creator>
		<pubDate>Sun, 08 Nov 2009 04:59:56 +0000</pubDate>
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		<description>@ Mohit: This is wrong, but we will rectify it later. 

BTW, there are 365 possible birthdays (if we ignore leap years) and not 7

Let others also try.</description>
		<content:encoded><![CDATA[<p>@ Mohit: This is wrong, but we will rectify it later. </p>
<p>BTW, there are 365 possible birthdays (if we ignore leap years) and not 7</p>
<p>Let others also try.</p>
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	<item>
		<title>By: mohit</title>
		<link>http://www.quickermaths.com/birthday-paradox/comment-page-1/#comment-348</link>
		<dc:creator>mohit</dc:creator>
		<pubDate>Sat, 07 Nov 2009 21:05:02 +0000</pubDate>
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		<description>1. (1/7)^23

2. (1/7)^57

3. when there are atleast 8 people

pls rectify if incorrect</description>
		<content:encoded><![CDATA[<p>1. (1/7)^23</p>
<p>2. (1/7)^57</p>
<p>3. when there are atleast 8 people</p>
<p>pls rectify if incorrect</p>
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