**Zeller’s Rule : **With this technique named after its founder Zeller, you can solve any ‘Dates and Calendars’ problems.

Zellers rule can be used to find the day on any particular date in the calendar in the history. All you have to know is the formula given below and how to use it.

**Zeller’s Rule Formula:**

F = K + [(13xM – 1)/5] + D + [D/4] + [C/4] – 2C

K = Date => for 25/3/2009, we take 25

In Zeller’s rule months start from march.

M = Month no. => Starts from March.

March = 1, April = 2, May = 3

Nov. = 9, Dec = 10, Jan = 11

Feb. = 12

D = Last two digits of the year, using previous year for January and February. Thus for 2009 = 09

C = The first two digits of century => for 2009 = 20

Example: 25/03/2009

F = 25 + [{(13 x1)- 1}/5] + 09 + 09/4 + 20/4 – (2 x 20)

= 25 + 12/5 + 09 + 09/4 + 20/4 – 2×20

=25+2+09+2+5-40 **[ We will just consider the integral value and ignore the value after decimal]**

= 43 – 40 =

Replace the number with the day using the information given below.

1 = Monday

2 = Tuesday

3 = Wednesday

4 = Thursday

5 = Friday

6 = Saturday

7 or 0 = Sunday

So it’s Wednesday on 25th march, 2009.

If the number is more than 7, divide the no. by 7. The remainder will give you the day.

I shall be very grateful if anyone of you can provide me the java script for this formula, so that I can post it here for everyone’s convenience.

Thanks in advance. I hope you will find the above method very useful.

you may find another post named, cyclicity very interesting.

**Vineet Patawari – PGDM, ACA, B.COM (H)**

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