Comments on: Finding Cube Root – Vedic Maths Way

By: Vineet Patawari

Vineet Patawari — Fri, 29 Mar 2013 17:31:54 +0000

Ayush, thanks for sharing your experience. I’m glad that the trick helped in you.

By: Akarsh

Akarsh — Fri, 29 Mar 2013 15:36:36 +0000

dis process is really correcct and very very help full !!! … its amazing !!

By: Luciana

Luciana — Fri, 30 Nov 2012 07:56:57 +0000

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By: Ali

Ali — Fri, 30 Nov 2012 07:31:07 +0000

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By: rahul

rahul — Mon, 19 Nov 2012 07:16:12 +0000

Thanks quicker maths.com,,, it is really very helpful in order to find the cube of any number !!!Keep it up good job

By: reetesh malvi

reetesh malvi — Thu, 27 Sep 2012 14:51:53 +0000

its really amaizing

thnx sir

By: Ayush Kumar Rai

Ayush Kumar Rai — Tue, 11 Sep 2012 18:42:08 +0000

vineet Bhaiya I got info abt this site from google wen i was practising acct in the mid ni8 suddenly i got a sum where relation of cost and sales was required.I saw the trick you learn from jha sir and i completed the sum. Thank you very Much Bhaiya

Your site and your help to students like me is awsome.

By: srijit mukherjee

srijit mukherjee — Tue, 11 Sep 2012 09:37:34 +0000

see my way plz/

By: srijit mukherjee

srijit mukherjee — Tue, 11 Sep 2012 09:35:48 +0000

actually cube root of any no can be found very easily.(even not perfect cubes). let 123456 is a no. now from the units place mark every tthree digits. for eg. here mark 456 nd 123. now find the nearest cube to 123. it is(4 cube) ie 64. nw subtract 64 from 123. now gthe remainder is 59. nw bring down the remaining no. therefore the no formed is 59456.

then, in the eqtn, 300x^2y + 30xy^2 +y^3=59456(nw put the value of x=4) therefore the eqtn will be 4800y + 120y^2 + y^3. nw by trial and error method put the values of y in the eqtn nd find for which value of y the no formed will be the nearest to 59456. therefore (40+y) is the nearest cube root of 123456. this can be done for any no.

By: srijit mukherjee

srijit mukherjee — Tue, 11 Sep 2012 09:35:06 +0000

i am a student of class 9. if i am wrong friends then tell me. it is a time of learning. to mr. vineet am i right?///////////////