**Fruit Seller’s Paradox- **Each of two apple women had 30 apples for sale. The first sold hers at the rate of 2 for a nickel, the second at the rate of 3 for a nickel. At the end of the day their respective receipts were 75 cents and 50 cents, or $1.25 in all.

The next day the women decided to do business together, so they pooled their 60 apples and sold them at the rate of 5 for a dime (2 for a nickel plus 3 for a nickel). Upon counting their joint receipts at the end of the day they were dismayed to find that they had only $1.20. They searched all about them for that other nickel, and wound up by bitterly accusing each other of having taken it. Where was it? (1 Nickel = 5 Cents)

help me find some interesting entertaing competitive mathematical puzzles

Nice fill someone in on and this post helped me alot in my college assignement. Thanks you seeking your information.

The cost of each apple at 2 for a nickle is 2.5 cents a peice, while at 3 for a nickle is 1.666 ~ 1.67 cents a peice. To get the original $1.25 for selling all 60 apples, they must be sold at (1.67+2.5)/2 = 2.08 cents a peice. However, the 60 apples are sold at 2 cents a peice. Meaning a loss of 0.08 * 60 = 4.8 cents which is approximately a nickle. And thus the mystery of the missing nickle is solved

It’s not that difficult guys…atleast some of you should give a try!!

If you want I can give you the answer 🙂