# Chocolate Maths Trick

You can do this little cute mathematics trick with your friends or girl-friends. This trick will be applicable for year 2011. Let me know if you like it.

**Age by Chocolate – Mathematics Trick**

Step 1. Choose the number of times a week that you would like to have chocolate between 1 and 10.

Step 2. Multiply this number by 2. Add 5. Multiply it by 50.

Step 3. If you have already had your birthday this year add 1761. If you haven’t, add 1760.

Step 4. Now subtract the four digit year that you were born. You should end up with a three digit number.

The first digit is the number of times you like chocolate in the week.

The last two digits is your age!

Let me explain this to you using my date of birth as an example. You can try with yours.

Step 1. I choose to eat chocolate 6 times in a week. I love chocolates ðŸ™‚

Step 2. 6*2=12+5=17*50=850

Step 3. My birthdate is 5^{th} April 1983 and my birthday in 2011 is yet to come. It will be there tomorrow ðŸ˜‰

So we have to add 1761 to 850 = 2611

Step 4. Subtracting 1984 from 2611 gives 627.

Here 6 is the number of time I would like to have chocolate and 27 is my age. Isnâ€™t it fun?

So for those who just want to have fun, go and do the trick with your pals. Those who want to exercise their grey cells, try and tell me whatâ€™s going on here.

awesome dude give me more psots like this

but is there any specific reason about how this trick works? i mean to ask what is the mechanism behind this ????how does i work?(just too curious to knoe!)

but is there any specific reason why this method wunt work if sumone’s age is greater than 100????(just too curious to know!)

plzz ignore this question as it was asked bymistakely!i have submitted d real ques above this!

In response to Mr.Mayank comment,

For those who are in the age group of 100 and more upto 199 there is one more step to follow

Step 5:Now subtract 100 from the result of Step 4.

say u choose x chocolates, then u get (50*(2x+5)) = 100x+250,

say we had b’day in 2011, so we will add 1761, we get 100x+2011, now we will subtract (2011 – P), where P is our present age, i.e. 1981 if 20 years old,

so we get 100x+2011-2011+P= P+100x, rest is undestood

however this method wont work if we are more than 100 years old :p check it.

If n is the number you are doing is

100n+250+1761-1984

Which will always work and not in 2011.