A man had twelve toothpicks in front of him. He took one away. Now he had nine in front of him. How is this possible?
Leave your answers below.
Here is an interesting mathematical puzzle for you.
You have a pile of 24 coins. Twenty-three of these coins have the same weight, and one is heavier. Your task is to determine which coin is heavier and do so in the minimum number of weighings. You are given a beam balance (scale), which will compare the weight of any two sets of coins out of the total set of 24 coins. How many weighings are required to identify the heavier coin?
Leave your answers below.
Once upon a time, an old lady went to sell her vast quantity of eggs at the local market.
When asked how many she had, she replied:
Son, I can’t count past 100 but I know that.
If you divide the number of eggs by 2 there will be one egg left.
If you divide the number of eggs by 3 there will be one egg left.
If you divide the number of eggs by 4 there will be one egg left.
If you divide the number of eggs by 5 there will be one egg left.
If you divide the number of eggs by 6 there will be one egg left.
If you divide the number of eggs by 7 there will be one egg left.
If you divide the number of eggs by 8 there will be one egg left.
If you divide the number of eggs by 9 there will be one egg left.
If you divide the number of eggs by 10 there will be one egg left.
Finally. If you divide the Number of eggs by 11 there will be NO EGGS left!
How many eggs did the old lady have?
Leave your answers below.
Very often we have to deduct a number from numbers like 1000, 10000, 100000 and so on.
This Vedic Maths Subtraction method found as sutra in ancient vedas, is given below is very useful for such subtractions.
Memory Trick: ALL FROM 9 AND THE LAST FROM 10
Use the formula all from 9 and the last from 10, to perform instant subtractions.
For example 1000 – 357 = ? (subtraction from 1000)
We simply take each figure in 357 from 9 and the last figure from 10.
Step 1. 9-3 = 6
Step 2. 9-5 = 4
Step 3. 10-7 = 3
So the answer is 1000 – 357 = 643
And that’s all there is to it!
This always works for subtractions from numbers consisting of a 1 followed by noughts: 100; 1000; 10,000 etc.
Similarly 10,000 – 1049 = 8951 (subtraction from 10000)
9-1 = 8
9-0 = 9
9-4 = 5
10-9 = 1
So answer is 8951,
For 1000 – 83, in which we have more zeros than figures in the numbers being subtracted, we simply suppose 83 is 083.
So 1000 – 83 becomes 1000 – 083 = 917
Corollary: If last term is 0, keep that last term as 0 and subtract the last non Zero term from 10 .
Illustration: 10000 – 920 = 10000 – 0920 = (9-0) (9-9) (10-2) 0 =9080
Illustration: 100000 – 78010 = (9-7) (9 – 8 ) (9- 0) (10 – 1) 0 = 21990
If you like this vedic maths subtraction, please leave a comment.
Management Aptitude Test or MAT Syllabus
MAT is the MBA entrance test conducted country-wide by the Centre for Management Services (CMS) of All India Management Association (AIMA). It is usually conducted four times in a year in February, May, September and December. MAT is conducted in all major cities in the country and in leading cities abroad.
The minimum qualification for appearing in MAT is graduation in any discipline from any recognized University or equivalent recognized degree. A final year student in any undergraduate (i.e., B.A., B.Sc., B.Com., B.Tech., etc.,) can also appear provisionally. Usually, there is a minimum percentage requirement in graduation, which is different for different MIs / University.
The Management Aptitude Test or MAT is the test conducted by All India Management Testing Service for entering into MBA or equivalent post graduate programmes.
There are five papers in MAT:
1. Language Comprehension
2. Mathematical Skills
3. Data Analysis
4. Intelligence & Critical Reasoning
5. Indian & Global Environment Section
Total Questions: 200
Time: 150 minutes
Correct attempt: 1 mark
Incorrect attempt: Negative marking not specified
Reading Comprehension 40
Data Interpretation/Data sufficiency 40
Quantitative Aptitude 40
Logical and Critical reasoning 40
General Awareness** 40
**Scores are based on the first four sections only, the decision to consider scores of the General Awareness section are left to the institutes.
Vedic Multiplication: This method of multiplication which is from Vedic Maths will make it very easy to multiply two numbers when sum of the last digits is 10 and previous parts are the same
You will get the answer in two parts.
First part, to get left hand side of the answer: multiply the left most digit(s) by its successor
Second part, to get right hand side of the answer: multiply the right most digits of both the numbers.
First part: 4 x (4+1)
Second part: (4 x 6)
Combined effect: (4 x 5) | (4 x 6) = 2024
*| is just a separator. Left hand side denotes tens place, right hand side denotes units place
37 x 33 = (3 x (3+1)) | (7 x 3) = (3 x 4) | (7 x 3) = 1221
11 x 19 = (1 x (1+1)) | (1 x 9) = (1 x 2) | (1 x 9) = 209
As you can see this method is corollary of “Squaring number ending in 5”
It can also be extended to three digit numbers like :
E.g. 1: 292 x 208.
Here 92 + 08 = 100, L.H.S portion is same i.e. 2
292 x 208 = (2 x 3) x 10 | 92 x 8 (Note: if 3 digit numbers are multiplied, L.H.S has to be multiplied by 10)
60 | 736 (for 100 raise the L.H.S. product by 0) = 60736.
E.g. 2: 848 X 852
Here 48 + 52 = 100,
L.H.S portion is 8 and its next number is 9.
848 x 852 = 8 x 9 x 10 | 48 x 52 (Note: For 48 x 52, use methods shown above)
720 | 2496
[L.H.S product is to be multiplied by 10 and 2 to be carried over because the base is 100].
Eg. 3: 693 x 607
693 x 607 = 6 x 7 x 10 | 93 x 7 = 420 / 651 = 420651.
Note: This Vedic Maths method can also be used to multiply any two different numbers, but it requires several more steps and is sometimes no faster than any other method. Thus try to use it where it is most effective
How do you like this Vedic Maths technique, please let us know. You can also share this with your friends.
Finding square of any number with unit’s digit being 5 is the most common, yet very interesting trick of Vedic Maths. Using this technique you can find the square of any number ending in 5 very easily. Also explore a quick method of squaring numbers ending in 9. Given below is the step by step explanation of this Vedic Maths Method.
Let us take a 2 digit number in generic form, say the number is a5 (=10a+5), where a is the digit in ten’s place
Square of a5= a x (a+1) | 25
That means a is multiplied by the next higher number, i.e. (a+1). Now let’s take example of a real number ending in 5, say 45.
452 = Left hand side of the answer will be 4 multiplied by its successor i.e. 5 and the right hand side part will always be 25 for squares of numbers of which the unit’s digit is 5.
Giving the answer a x (a+1) | 25 ( | stands for concatenation}
i.e. 4 x (4+1) | 25 = 4 x 5 | 25 = 2025
Similarly we can proceed for 3 digit numbers ending in 5
Few more examples:
952=9 x 10 | 25 =9025
1252 = 12 x 13 | 25 = 15625
5052 = 50 x 51 | 25 = 255025
Find out the square of 85, 245, 145, 35, 15, and 95?
Answer: 7225, 60025, 21025, 1225, 225, 9025
Please let us know if you like this Vedic Maths trick
Syllabus for CAT 2009
There is no prefixed pattern for CAT.Â The syllabus given below is based on the experience of previous CATs. The list may not be exhaustive but almost the entire gamut is covered. CAT 2009 will be online
Ratios and Proportion, Ratios, Percentages, In-equations , Quadratic and linear equations, Algebra, Profit & Loss, Averages, Percentages, Partnership, Time-Speed-Distance, Work and time, Number system, HCF, LCM, Geometric Progression, Arithmetic progression, Arithmetic mean, Geometric mean , Harmonic mean, Median, Mode, Number Base System, BODMAS, Mensuration, Alligation & Mixtures, Work, Pipes and Cisterns, Simple Interest & Compound Interest, Set Theory, Venn Diagram, Installment Payments, Partnership, Clocks, Probability, Permutations & Combinations, Trigonometry, Vectors, Binomial Expansion, Co-ordinate geometry, Geometry (Lines, angles, Triangles, Spheres, Rectangles, Cube, Cone etc), Logarithm, Calendar, Maxima & Minima Progression, Surds & Indices and Complex numbers, Pipes and Cisterns, Functions etc.
Data Interpretation based on text, Data Interpretation based on graphs and tables. Graphs can be Column graphs, Bar Graphs, Line charts, Pie Chart, Graphs representing Area, Venn Diagram, Data Sufficiency etc.
Critical reasoning, Visual reasoning, Assumption-Premise-Conclusion, Assertion and reasons, Statements and assumptions, identifying valid inferences , identifying Strong arguments and Weak arguments, Statements and conclusions, Cause and Effect, Identifying Probably true, Probably false, definitely true, definitely false kind of statement, Linear arrangements, Matrix arrangements, Puzzles, Family tree problem , Symbol Based problems, Coding and decoding , Sequencing , identifying next number in series etc.
Comprehension of passage, Verbal Reasoning, Syllogisms , Contextual usage, Analogies, Antonyms, Fill In the Blanks, Jumbled paragraphs with 4 or 5 sentences, Foreign language words used in English, Sentence completion, Sentence correction, odd man out, idioms, one word substitution, Different usage of same word, Errors in word choice, mania & phobia, Incorrect words, Mood, Conditionals & Multiple Usage , Punctuation, Proverb, Phrasal verb etc.
Vedic Mathematics is the name given to the ancient system of Mathematics which was rediscovered from the Vedas between 1911 and 1918 by Sri Bharati Krsna Tirthaji (1884-1960). The aim of such sutra is to simplify the entire calculations and arithmetical operations.
Vedic Maths Course
There are 16 sutras in vedic mathematics as per Sri Bharati Krsna Tirthaji Maharaj. The below mentioned list of topics (course content) is how I look at it.
Through www.QuickerMaths.com (QM) I’ll try to cover all the above vedic maths related topics. Lot of other topics, techniques, shortcuts will be part of QM. Mathematical games, puzzles, riddles, etc. are also included to make every kid sharp.