You are in a room with 2 doors

You are in a room with 2 doors leading out. Behind 1 door is a coffer overflowing with jewels and gold, along with an exit. Behind the other door is an enormous, hungry lion that will pounce on anyone opening the door. You do not know which door leads to the treasure and exit, and which door leads to the lion. In the room you are in are 2 individuals. The first is a knight, who always tells the truth, and a knave, who always lies. Both of these individuals know what is behind each door. You do not know which individual is the knight, or which one is the knave. You may ask one of the individuals exactly 1 question. What should you ask in order to be certain that you will open the door with the coffer behind it, instead of the hungry lion?

Leave your answer below.

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Vedic Maths Workshop

This is to announce that is conducting a workshop on VEDIC MATHEMATICS on this Sunday and Monday, 19th and 20th July, 2009.

The workshop will be on VEDIC MATHEMATICS [quicker calculation techniques that would help you to increase your calculation speed tremedously sharpen your intellect. The seminar will by me.

To know about me – click here.

Seminar Details

Days & Dates – Sunday and Monday, 19th and 20th July, 2009
Time 10.30 am to 1.30 pm on both days
Venue BG-109, Sector – II, Salt Lake, Kolkata -700091
Fees: INR. 750/ Student (inclusive of charges for study material)
You can pay by Cash, Cheque or Demand Draft, payable at Kolkata (in favour of “Preksha Consultancy Private Limited”)
The fee needs to be deposited on or before 17th July, 2009 (Friday) at BG-109, Sector – II, Salt Lake, Kolkata -700091.

The feedback from students from eminent colleges, specially students preparing for competitive examinations like CAT, GMAT, GRE, MAT, etc. is very encouraging and I am happy to see such acceptance of Vedic Maths: a great gift from the sages of India.

For any clarification or further information, please feel free to mail me at vineetpatawari [at] gmail [dot] com.

Vineet Patawari

You have a pile of 24 coins

Here is  an interesting mathematical puzzle for you.

You have a pile of 24 coins. Twenty-three of these coins have the same weight, and one is heavier. Your task is to determine which coin is heavier and do so in the minimum number of weighings. You are given a beam balance (scale), which will compare the weight of any two sets of coins out of the total set of 24 coins. How many weighings are required to identify the heavier coin?

Leave your answers below.

Once upon a time

Once upon a time, an old lady went to sell her vast quantity of eggs at the local market.
When asked how many she had, she replied:
Son, I can’t count past 100 but I know that.

If you divide the number of eggs by 2 there will be one egg left.
If you divide the number of eggs by 3 there will be one egg left.
If you divide the number of eggs by 4 there will be one egg left.
If you divide the number of eggs by 5 there will be one egg left.
If you divide the number of eggs by 6 there will be one egg left.
If you divide the number of eggs by 7 there will be one egg left.
If you divide the number of eggs by 8 there will be one egg left.
If you divide the number of eggs by 9 there will be one egg left.
If you divide the number of eggs by 10 there will be one egg left.
Finally. If you divide the Number of eggs by 11 there will be NO EGGS left!

How many eggs did the old lady have?

Leave your answers below.

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Vedic Maths Subtraction

Learn Amazingly Fast Vedic Mathematics Subtraction

Very often we have to deduct a number from numbers like 1000, 10000, 100000 and so on.

This Vedic Maths Subtraction method found as sutra in ancient vedas, is given below is very useful for such subtractions.


Use the formula all from 9 and the last from 10, to perform instant subtractions.

For example 1000 – 357 = ?      (subtraction from 1000)

We simply take each figure in 357 from 9 and the last figure from 10.
Step 1. 9-3 = 6
Step 2. 9-5 = 4
Step 3. 10-7 = 3

So the answer is 1000 – 357 = 643
And that’s all there is to it!

This always works for subtractions from numbers consisting of a 1 followed by noughts: 100; 1000; 10,000 etc.
Similarly 10,000 – 1049 = 8951      (subtraction from 10000)

9-1 = 8
9-0 = 9
9-4 = 5
10-9 = 1

So answer is 8951,

For 1000 – 83, in which we have more zeros than figures in the numbers being subtracted, we simply suppose 83 is 083.
So 1000 – 83 becomes 1000 – 083 = 917

Corollary: If last term is 0, keep that last term as 0 and subtract the last non Zero term from 10 .

Illustration: 10000 – 920 = 10000 – 0920 = (9-0) (9-9) (10-2) 0 =9080

Illustration: 100000 – 78010 = (9-7) (9 – 8 ) (9- 0) (10 – 1) 0 = 21990

If you like this vedic maths subtraction, please leave a comment.


Management Aptitude Test or MAT Syllabus

MAT is the MBA entrance test conducted country-wide by the Centre for Management Services (CMS) of All India Management Association (AIMA). It is usually conducted four times in a year in February, May, September and December. MAT is conducted in all major cities in the country and in leading cities abroad.


The minimum qualification for appearing in MAT is graduation in any discipline from any recognized University or equivalent recognized degree. A final year student in any undergraduate (i.e., B.A., B.Sc., B.Com., B.Tech., etc.,) can also appear provisionally. Usually, there is a minimum percentage requirement in graduation, which is different for different MIs / University.

MAT Syllabus
The Management Aptitude Test or MAT is the test conducted by All India Management Testing Service for entering into MBA or equivalent post graduate programmes.

There are five papers in MAT:
1. Language Comprehension
2. Mathematical Skills
3. Data Analysis
4. Intelligence & Critical Reasoning
5. Indian & Global Environment Section

Paper Pattern:

Total Questions: 200
Time: 150 minutes

Marks allocation:
Correct attempt: 1 mark
Incorrect attempt: Negative marking not specified

Section Questions
Reading Comprehension       40
Data Interpretation/Data sufficiency     40
Quantitative Aptitude      40
Logical and Critical reasoning        40
General Awareness**       40
**Scores are based on the first four sections only, the decision to consider scores of the General Awareness section are left to the institutes.

Multiply 2 numbers, sum of whose unit places is 10

Vedic Multiplication: This method of multiplication which is from Vedic Maths will make it very easy to multiply two numbers when sum of the last digits is 10 and previous parts are the same

You will get the answer in two parts.

First part, to get left hand side of the answer: multiply the left most digit(s) by its successor

Second part, to get right hand side of the answer: multiply the right most digits of both the numbers.


First part: 4 x (4+1)

Second part: (4 x 6)

Combined effect:  (4 x 5)  | (4 x 6) = 2024

*| is just a separator. Left hand side denotes tens place, right hand side denotes units place

More Examples

37 x 33 = (3 x (3+1)) |  (7 x 3) = (3 x 4) | (7 x 3) = 1221

11 x 19 = (1 x (1+1)) |  (1 x 9) = (1 x 2)  | (1 x 9) = 209

As you can see this method is corollary of  “Squaring number ending in 5”

It can also be extended to three digit numbers like :

E.g. 1: 292 x 208.

Here 92 + 08 = 100, L.H.S portion is same i.e. 2

292 x 208 = (2 x 3) x 10 | 92 x 8  (Note: if 3 digit numbers are multiplied, L.H.S has to be multiplied by 10)

60 | 736 (for 100 raise the L.H.S. product by 0) = 60736.

E.g. 2: 848 X 852

Here 48 + 52 = 100,

L.H.S portion is 8 and its next number is 9.

848 x 852 = 8 x 9 x 10 | 48 x 52 (Note: For 48 x 52, use methods shown above)

720 | 2496

= 722496.

[L.H.S product is to be multiplied by 10 and 2 to be carried over because the base is 100].

Eg. 3: 693 x 607

693 x 607 = 6 x 7 x 10 | 93 x 7 = 420 / 651 = 420651.

Note: This Vedic Maths method can also be used to multiply any two different numbers, but it requires several more steps and is sometimes no faster than any other method. Thus try to use it where it is most effective

How do you like this Vedic Maths technique, please let us know. You can also share this with your friends.

How to Quickly Find Square of Any Number Ending in 5

Finding square of any number with unit’s digit being 5 is the most common, yet very interesting trick of Vedic Maths.  Using this technique you can find the square of any number ending in 5 very easily.  Also explore a quick method of squaring numbers ending in 9. Given below is the step by step explanation of this Vedic Maths Method.

Let us take a 2 digit number in generic form, say the number is a5 (=10a+5), where a is the digit in ten’s place

Square of a5= a x (a+1) | 25

That means a is multiplied by the next higher number, i.e. (a+1). Now let’s take example of a real number ending in 5, say 45.

452 = Left hand side of the answer will be 4 multiplied by its successor i.e. 5 and the right hand side part will always be 25 for squares of numbers of which the unit’s digit is 5.

Giving the answer a x (a+1) | 25 ( |     stands for concatenation}

i.e. 4  x  (4+1) | 25 = 4 x 5 | 25 = 2025

Similarly we can proceed for 3 digit numbers ending in 5

Few more examples:

952=9 x 10 | 25 =9025

1252 = 12 x 13 | 25 = 15625

5052 = 50 x 51 | 25 = 255025

Test yourself

Find out the square of 85, 245, 145, 35, 15, and 95?

Answer: 7225, 60025, 21025, 1225, 225, 9025

Please let us know if you like this Vedic Maths trick