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	<title>Comments on: Question of Probability</title>
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	<description>Vedic Maths Tricks &#124; Puzzles, Brainteasers &#38; Riddles</description>
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		<title>By: sagar</title>
		<link>http://www.quickermaths.com/question-of-probability/comment-page-1/#comment-2586</link>
		<dc:creator>sagar</dc:creator>
		<pubDate>Tue, 05 Apr 2011 07:53:46 +0000</pubDate>
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		<description>1-1/3=2/3.</description>
		<content:encoded><![CDATA[<p>1-1/3=2/3.</p>
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		<title>By: ADITYA</title>
		<link>http://www.quickermaths.com/question-of-probability/comment-page-1/#comment-1053</link>
		<dc:creator>ADITYA</dc:creator>
		<pubDate>Thu, 10 Jun 2010 18:18:34 +0000</pubDate>
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		<description>1/6</description>
		<content:encoded><![CDATA[<p>1/6</p>
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	<item>
		<title>By: sanyam</title>
		<link>http://www.quickermaths.com/question-of-probability/comment-page-1/#comment-457</link>
		<dc:creator>sanyam</dc:creator>
		<pubDate>Mon, 30 Nov 2009 12:38:12 +0000</pubDate>
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		<description>what are the 2 favourable cases?</description>
		<content:encoded><![CDATA[<p>what are the 2 favourable cases?</p>
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	<item>
		<title>By: Debatra</title>
		<link>http://www.quickermaths.com/question-of-probability/comment-page-1/#comment-455</link>
		<dc:creator>Debatra</dc:creator>
		<pubDate>Mon, 30 Nov 2009 10:10:42 +0000</pubDate>
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		<description>abc,acb,bac,*bca,*cab,cba
asterix marked are condition</description>
		<content:encoded><![CDATA[<p>abc,acb,bac,*bca,*cab,cba<br />
asterix marked are condition</p>
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		<title>By: praveen</title>
		<link>http://www.quickermaths.com/question-of-probability/comment-page-1/#comment-447</link>
		<dc:creator>praveen</dc:creator>
		<pubDate>Fri, 27 Nov 2009 15:28:18 +0000</pubDate>
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		<description>is the ans. 2/3.?????????</description>
		<content:encoded><![CDATA[<p>is the ans. 2/3.?????????</p>
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	<item>
		<title>By: mohit</title>
		<link>http://www.quickermaths.com/question-of-probability/comment-page-1/#comment-439</link>
		<dc:creator>mohit</dc:creator>
		<pubDate>Thu, 26 Nov 2009 16:32:12 +0000</pubDate>
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		<description>2/3</description>
		<content:encoded><![CDATA[<p>2/3</p>
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	<item>
		<title>By: Prateek Mehtaq</title>
		<link>http://www.quickermaths.com/question-of-probability/comment-page-1/#comment-432</link>
		<dc:creator>Prateek Mehtaq</dc:creator>
		<pubDate>Thu, 26 Nov 2009 09:52:56 +0000</pubDate>
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		<description>total cases - 6
favourable cases - 2
probability - 2/6 = 1/3</description>
		<content:encoded><![CDATA[<p>total cases &#8211; 6<br />
favourable cases &#8211; 2<br />
probability &#8211; 2/6 = 1/3</p>
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