Something for the Chickens
A simple mathematical logic says -
odd + odd = even
odd + even = odd
even + odd = odd
even + even = even
Now since you know this have a look at the small riddle below -
A friend of mine runs a small poultry farm in Bangalore. She took me round to see the place. I counted the number of chickens. There were 27 of them. And there were 4 enclosures. I noticed that in each enclosure there were an odd number of chickens.
Can you tell how many there were in each enclosure?
You may also like:
Who is behind QuickerMaths?
I am Vineet Patawari - PGDM (IIM Indore), ACA, B.Com(H). My passion for Mathematics, specially Vedic Maths encouraged me to start QuickerMaths
I believe that if trained properly using powerful tools like Vedic Maths, the immense intellect of human mind can be ignited instantly - find out more
Get Maths Tricks by Email
Recent Comments
A, B and C can do a piece of work in 40, 60 and 120... – 07Feb12
as a night watchman he is not supposed to sleep during the night . as... – 06Feb12
ramlal is a night watchman and he is sleep on duty therefor boss fire him,... – 06Feb12
Dear, It is good..... But I was already given this question on 06-12-2011 at 11.08... – 05Feb12
he rewarded the watchman because watchman saved his life by warning him that the plane... – 05Feb12
Most Popular
- 100% Finding Cube Root – Vedic Maths Way
- 67% Shortcut to Find Square of a Number
- 57% Shortcut Method for Multiplication
- 56% Shortcut to find the Cube of a number
- 53% Squaring any 2-digit number
- 49% Divisibility Rule of 7, 13, 17, 19, 23, 29, 31, 37, 41, 43 and 47
- 45% Division in Vedic Mathematics
- 45% Herons Method of Finding Roots
- 43% You can make a difference
- 41% Quicker Maths by M Tyra
- 40% Quick calculations for extremely large numbers
- 39% Divisibility Rules for 7 , 11 and 13
- 37% How to convert from decimal to other number systems
- 36% Quick Multiplication up to 20 x 20
- 35% Logical Reasoning Books
November 10th, 2011 - 18:29
its not possible to have 4 odd numbers which sums to an odd no
March 26th, 2011 - 16:53
23
1
1
1
1 chick was the friend herself. lol
February 6th, 2011 - 19:59
no answer if provided law in ques is correct
January 11th, 2011 - 23:58
please give me the list of competitions of maths for class9plzzzzzzzzzzzzzzz
January 1st, 2011 - 23:09
23
)
1
1
1
one chicken was in friends hand ie outside the coup. (Tht voz 4 dinner!! lol
November 17th, 2010 - 16:13
Excellent brief and this article helped me alot. Say thank you I looking for your information….
November 10th, 2010 - 22:44
there’s no answer for this question
November 4th, 2010 - 11:11
i believe karteek is right…..
October 25th, 2010 - 23:19
all 3 contains 9 chickens each and those 3 will be in another container
October 25th, 2010 - 22:28
there will be 7 chickens each in 3 enclosre while 6 chicken in 4th one
October 26th, 2010 - 19:08
sory i m wrong
October 24th, 2010 - 17:02
All the enclosures were around one another i.e. there was only one big enclosure which contained another enclosure and so on. In the last enclosure there were the 27 chickens.
March 26th, 2011 - 02:24
well done.i think ur right
October 24th, 2010 - 15:29
There are 3 enclosures containing say 9 chickens each. All three enclosures are inside a big enclosure.
October 24th, 2010 - 11:25
each of the 4 enclosuress have 6 chickens but they each share 3 chickens in an area common to the 4 enclosures.
October 24th, 2010 - 11:22
9 chickens in each coop. each coop has 6 chickens but then they share 3 chickens in a common portion of the coop.
October 24th, 2010 - 10:41
if that specified in question is true,
(odd + odd) + (odd + odd) = odd
=>even + even = odd
=>contradiction
———————
anupkumar55@gmail.com
October 24th, 2010 - 10:36
Mathematically 27 can not be divided in 4 section, where all section contains odd numbers. Hence I feel 3 enclosure all having odd numbers and the fourth enclosure having zero number of chickens in it.
October 24th, 2010 - 10:44
but zero is not odd!!