Perfect Square Puzzles
Squaring Puzzles- Find below 2 interesting puzzles related to square of some number. Hope you will like them.
Puzzle 1
The square of 13 is 169. Take the last digit of the square, 9, and place it in the middle, making 196. This is the square of 14, the next number above 13.
What are the next numbers which also have this property?
Puzzle 2
The following multiplication example uses every digit from 0 to 9 at least once. Letters have been substituted for the digits. Can you replace the letters and make the original multiplication problem?
B O G
x B O G
_______________
L Y L E
G G U L
T U O O
___________________
U N I T O E
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I am Vineet Patawari - PGDM (IIM Indore), ACA, B.Com(H). My passion for Mathematics, specially Vedic Maths encouraged me to start QuickerMaths
I believe that if trained properly using powerful tools like Vedic Maths, the immense intellect of human mind can be ignited instantly - find out more
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December 12th, 2011 - 20:12
sir your puxxles are outstanding
July 17th, 2011 - 01:19
Square of 15=225,last digit is 5.
which is middle number of successive digit square i.e16 square = 256
July 5th, 2011 - 21:49
superb tricks used plz upload sum more
October 2nd, 2010 - 23:34
amazing
September 20th, 2010 - 15:55
12 square is 144
21 square is 441
By interchanging number we get a new puzzle.
yet another :
13 square is 169
31 square is 961.
September 20th, 2010 - 15:52
12 square is 144
21 square is 441
By interchanging number we get a new puzzle.
September 20th, 2010 - 12:26
13 is the only number with property that it’s square and that of it’s successor concide after interchanging last 2 digits of square of latter.
int ten(int x)
{
if(x<10)
return x;
else
{
x = x/10;
x =x%10;
return x;
}
}
int zero(int x)
{
return (x%10);
}
int newnum(int x)
{
x=10*ten(x)+zero(x);
return x;
}
int rev(int x)
{
int s = 0;
s+=10*(x%10);
x=x/10;
s+=x;
return s;
}
int anoop(int x)
{
int i;
i = x/100;
return (i*100 + rev(x%100));
}
int main(void)
{
int x,limit,y,z;
printf("INPUT A LIMIT");
scanf("%d",&limit);
for(x=10;x<=limit;x++)
{
if((x*x)-anoop((x+1)*(x+1))==0)
printf("%d\n",x);
}
getch();
return 0;
}
September 20th, 2010 - 16:57
Hi Anoop,
Great efforts!!
but I think u have slightly misunderstood the problem… when u r saying – “….after interchanging last 2 digits of square of latter.”
Actually it’s the middle digit which is replacing the last digit. So if the square is a 5 digit number, the hundred’s digit is replaced by unit’s digit.
I hope now you will get the answer!