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9Aug/101

Quicker Maths by M Tyra

Today, let me confess something to all of you. I am sure this will help all the readers.

So here I go. This is regarding the name of the website - QuickerMaths.com. It is inspired by the name of the best mathematics books I have ever come across. This book helped me a lot in clearing CAT and reaching to IIM. The inspiration of creating an interactive platform (QuickerMaths.com) came from this book. As a token of appreciation and to do my bit today I will tell you about this book named -

Magical Book on Quicker Maths

Author: M. Tyra

About the book: The book will be a boon for the aspirants of today’s competitive exams irrespective of their background – whether they come from arts, science or commerce stream. Concepts have been clarified so well, that even if one is vaguely familiar with them as in the case of non-mathematics students, understanding will not be a problem. Direct formulae are beneficial for one and all. They save time and time is precious for everyone.

Must for Competitive Preparation

The book is profusely illustrated. Avoiding the temptation for haste and ending up with a cookbook, the author has put in two years of intensive effort and research. Ideas have been taken from available study material, number theory, readers’ suggestions and, finally Vedic mathematics.

Recently I purchased the latest edition of this book from an online book store Flipkart.com

Purchase Online - The list Price is Rs. 250; you get a Discount of 25% (Rs. 62) on Flipkart.com.

So you get it for: Rs. 188 (incl. of all taxes)

Those who have already read this book please give your feedback to help others

Author: Vineet Patawari

Popularity: 28%

Filed under: Competitive Exam Prep, Vedic Mathematics 1 Comment
16Jul/109

Take the Link Challenge – Win a Book

Take the Link Challenge

Today I thought it might be fun to do a bit of a fun challenge.

The challenge is very simple – You have to find the websites, blogs, web pages, etc. linking to QuickerMaths.com (QM) or any of its post.

As your answers you have to just paste the URL (link) of the website or blog where you have seen QM link.

Rules:

  1. The link might be a blogroll link like the one in the image below on fireup blog

QM Link on FireUp

2.  Link within the text referring to QM. That could be because someone copied any post from QM and pasted it elsewhere.

    The figure below shows an example of this on forum of www.caclubindia.com


    1. The link can be on a social networking site like facebook, orkut, etc. posted by you or someone else.
    2. The link could be a simple mention of the link - http://www.quickermaths.com or www.quickermaths.com or quickermaths.com

    (But it should be a link and not simple text)

    *You can even give the link of websites or blogs where you yourself have give QM’s link. When you posted the link doesn’t matter.

    **Links present on QuickerMaths.com website will not be considered.

    I assure you it will be a fun filled experience and your “googling” skills will improve a lot.

    The winner will get the most amazing book on Vedic Mathematics by the father of Vedic Maths - Bharati Krsna Tirthaji Maharaja

    Vedic Maths book

    Vedic Maths book

    To know more about the book – visit http://vedicmathsindia.org/view_detail1.htm

    While giving your responses as comment below –

    • Mention your full name in name space
    • Mention your email address in email space
    • Mention http://www.quickermaths.com in the website space

    I will collect the address after announcing the winner to send the prize.

    Popularity: 34%

    Filed under: Competitive Exam Prep 9 Comments
    7Mar/103

    Vedic Mathematics Techniques for Finding HCF

    Vedic Maths Trick to find the HCF of Algebraic Expressions

    To appreciate the Vedic Maths process of finding the HCF you first need to know the other methods taught in school. I am giving you two other methods to compare with.

    Example 1: Find the H.C.F. of x^2 + 5x + 4 and x^2 + 7x + 6.

    Popularity: 38%

    Filed under: Vedic Mathematics Continue reading
    10Dec/090

    Checking of Calculations: Casting Out Nines

    While doing arithmetic calculations, we should normally check our calculation. But the checking should not be as tedious as the original problem. To solve this problem I am explaining below a very frequently used method which is discussed in Vedic Mathematics as well as by many other mathematicians.

    Vedic Sutra: Vedic Mathematics Technique

    Beejank: The Sum of the digits of a number is called Beejank. If the addition is a two digit number, then these two digits are also to be added up to get a single digit.

    Find the Beejank of 632174.

    As above we have to follow

    632174  --> 6 + 3 + 2 + 1 + 7 + 4 --> 23 --> 2 + 3 --> 5

    But a quick look gives 6 & 3 ; 2 & 7 are to be ignored because 6+3=9,2+7=9.

    Hence remaining 1 + 4 --> 5 is the beejank of 632174.

    Checking of Addition

    Thumb Rule: Whatever we do to the number, we also do to their digit sum: then the result                 we get from the digit sum of the number must be equal to the digit sum of the answer.

    For example: The number: 12+45+96+75+25 =253

    The digit sum = 3+9+6+3+7 =28=10=1

    Answer’s digit sum: 2+5+3 =10=1 (verified)

    Another example:  3.5+23.4+17.5 = 44.4

    The digit sum: 8+9+13=8+9+4=21=3

    Answer’s digit sum: 12=3 (verified)

    Casting Out Nines

    This method is also known as "casting-out-nines". The method involves converting each number into its "casting-out-nines" equivalent, and then redoing the arithmetic. The casting-out-nines answer should equal the casting-out-nines version of the original answer. Below are examples for using casting out nines to check addition.

    We get the casting-out-nines equivalent of a number by adding up its digits, and then adding up those digits, until you get a one digit number. If our answer is 9, then that becomes 0. As a short cut, we don't have to add in any of the 9's in our work, as these are the equivalent of 0. We can just "cast out" those 9's. For example, 19 becomes 1, without even adding 1 and 9 and getting 10, and then adding 1 and 0 and getting 1. As a further short cut, we can group numbers together which add up to 9, and replace them with 0. 2974 becomes 4, because we can cast out the 9 and the 2+7 (which is also 9 or 0). Well, let's try an arithmetic problem:

    137892     3

    + 92743   + 7

    ------    --

    230635     1

    3+7=10, casting out 9 we get 1.

    This rule is also applicable to subtraction, multiplication and up to some extent to division also

    In the next post I will explain the use of this method for all of them.

    Concept: CHECKING OF CALCULATIONS
    Beejank: The Sum of the digits of a number is called Beejank. If the addition is a two digit number, then these two digits are also to be added up to get a single digit.
    Find the Beejank of 632174.
    As above we have to follow
    632174  --> 6 + 3 + 2 + 1 + 7 + 4 --> 23 --> 2 + 3 --> 5
    But a quick look gives 6 & 3 ; 2 & 7 are to be ignored because 6+3=9,2+7=9.
    Hence remaining 1 + 4 --> 5 is the beejank of 632174.
    Checking of Addition
    Thumb Rule: Whatever we do to the number, we also do to their digit sum: then the result                 we get from the digit sum of the number must be equal to the digit sum of the answer.
    For example: The number: 12+45+96+75+25 =253
    The digit sum = 3+9+6+3+7 =28=10=1
    Answer’s digit sum: 2+5+3 =10=1 (verified)
    Another example:  3.5+23.4+17.5 = 44.4
    The digit sum: 8+9+13=8+9+4=21=3
    Answer’s digit sum: 12=3 (verified)
    This method is also known as "casting-out-nines". The method involves converting each number into its "casting-out-nines" equivalent, and then redoing the arithmetic. The casting-out-nines answer should equal the casting-out-nines version of the original answer. Below are examples for using casting out nines to check addition.
    We get the casting-out-nines equivalent of a number by adding up its digits, and then adding up those digits, until you get a one digit number. If our answer is 9, then that becomes 0. As a short cut, we don't have to add in any of the 9's in our work, as these are the equivalent of 0. We can just "cast out" those 9's. For example, 19 becomes 1, without even adding 1 and 9 and getting 10, and then adding 1 and 0 and getting 1. As a further short cut, we can group numbers together which add up to 9, and replace them with 0. 2974 becomes 4, because we can cast out the 9 and the 2+7 (which is also 9 or 0). Well, let's try an arithmetic problem:
    137892     3
    + 92743   + 7
    ------    --
    230635     1
    3+7=10, casting out 9 we get 1.
    This rule is also applicable to subtraction, multiplication and up to some extent to division also
    In the next post I will explain the use of this method for all of them.
    Concept: CHECKING OF CALCULATIONS
    Beejank: The Sum of the digits of a number is called Beejank. If the addition is a two digit number, then these two digits are also to be added up to get a single digit.
    Find the Beejank of 632174.
    As above we have to follow
    632174  --> 6 + 3 + 2 + 1 + 7 + 4 --> 23 --> 2 + 3 --> 5
    But a quick look gives 6 & 3 ; 2 & 7 are to be ignored because 6+3=9,2+7=9.
    Hence remaining 1 + 4 --> 5 is the beejank of 632174.
    Checking of Addition
    Thumb Rule: Whatever we do to the number, we also do to their digit sum: then the result                 we get from the digit sum of the number must be equal to the digit sum of the answer.
    For example: The number: 12+45+96+75+25 =253
    The digit sum = 3+9+6+3+7 =28=10=1
    Answer’s digit sum: 2+5+3 =10=1 (verified)
    Another example:  3.5+23.4+17.5 = 44.4
    The digit sum: 8+9+13=8+9+4=21=3
    Answer’s digit sum: 12=3 (verified)
    This method is also known as "casting-out-nines". The method involves converting each number into its "casting-out-nines" equivalent, and then redoing the arithmetic. The casting-out-nines answer should equal the casting-out-nines version of the original answer. Below are examples for using casting out nines to check addition.
    We get the casting-out-nines equivalent of a number by adding up its digits, and then adding up those digits, until you get a one digit number. If our answer is 9, then that becomes 0. As a short cut, we don't have to add in any of the 9's in our work, as these are the equivalent of 0. We can just "cast out" those 9's. For example, 19 becomes 1, without even adding 1 and 9 and getting 10, and then adding 1 and 0 and getting 1. As a further short cut, we can group numbers together which add up to 9, and replace them with 0. 2974 becomes 4, because we can cast out the 9 and the 2+7 (which is also 9 or 0). Well, let's try an arithmetic problem:
    137892     3
    + 92743   + 7
    ------    --
    230635     1
    3+7=10, casting out 9 we get 1.
    This rule is also applicable to subtraction, multiplication and up to some extent to division also
    In the next post I will explain the use of this method for all of them.

    Popularity: 13%

    Filed under: Vedic Mathematics No Comments
    16Nov/090

    Fast Multiplication by 5

    This fast calculation trick or vedic maths trick will teach you how to multiply any number by 5. The concept can be divided in two parts as shown-
    MULTIPLYING 5 TIMES AN EVEN NUMBER
    Memory Trick: Halve the number you are multiplying by and place a zero after the number.
    Example:
    i. 5 × 136, half of 136 is 68, add a zero for an answer of 680.
    ii. 5 × 874, half of 874 is 437; add a zero for an answer of 4370.
    MULTIPLYING 5 TIMES AN ODD NUMBER: subtract one from the number you are multiplying, then halve that number and place a 5 after the resulting number.
    Example:
    343 x 5 = (343-1)/2 | 5 =  1715

    This fast calculation trick or vedic maths trick will teach you how to multiply any number by 5. The concept can be divided in two parts as shown-

    MULTIPLYING 5 TIMES AN EVEN NUMBER

    Memory Trick: Halve the number you are multiplying by and place a zero after the number.

    Example:

    i. 5 × 136, half of 136 is 68, add a zero for an answer of 680.

    ii. 5 × 874, half of 874 is 437; add a zero for an answer of 4370.

    MULTIPLYING 5 TIMES AN ODD NUMBER: subtract one from the number

    Popularity: 13%

    Filed under: Vedic Mathematics Continue reading
    3Nov/091

    Vedic Multiplication of two numbers close to Hundred

    Vedic Method of Multiplication: Base System of multiplication

    Application: Multiplication of two numbers close to Hundred

    Case 1: Both numbers greater than 100.

    Example of vedic multiplication using above method

    • 103 x 104 = 10712

    The answer is in two parts: 107 and 12,

    107 is just 103 + 4 (or 104 + 3), and 12 is just 3 x 4.

    • Similarly 107 x 106 = 11342

    107 + 6 = 113 and 7 x 6 = 42

    123 x 103 = 12669

    (123 + 3) | (23 x 3) = 126 | 69 =12669 .

    If the multiplication of the offsets is more than 100 then this method won’t work. For example 123 x 105. Here offsets are 23 and 5.

    Multiplication of 23 and 5 is 115 which are more than 100. So this method won’t work.

    But it can still work with a little modification. Consider the following examples:

    Example 1

    122 x 123 = 15006

    Step 1: 22 x 23 = 506 (as done earlier)

    Step 2: 122 + 23 (as done earlier)

    Step 3: Add the 5 (digit at 100s place) of 506 to step 2

    Answer: (122 + 23 + 5) | (22 x 23) = 150 | 06 = 10506

    Example 2

    123 x 105 (Different representation but same method)

    123 + 5 = 128

    23 x 5 = 115

    128 | 115

    = 12915

    In the next post we will tell you about vedic multiplication, i.e.,  how to multiply two numbers lesser than the base (in this case 100)

    If you liked this method of vedic multiplication included in ancient Vedic Maths, Please leave a comment to let us know.

    Popularity: 32%

    Filed under: Speedy Calculation, Vedic Mathematics 1 Comment
    30Oct/0920

    Shortcut to find the Cube of a number

    Very often we have to find the cube, i.e. third power of 2 digit numbers. Cubes of very large numbers are rarely used.

    Cubes of all the single digits should be memorized. Find below the table of cubes of first ten natural numbers -

    13 = 1,              23 = 8,              33 = 27,            43 = 64,            53 = 125,

    63 = 216,          73 = 343,          83 = 512,          93 = 729,          103 = 1000

    To find the cube of any 2 digit number, we have to take the following steps

    First Step: The first thing we have to do is to put down the cube of the tens-digit in a row of 4 figures. The other three numbers in the row of answer should be written in a geometrical ratio in the exact proportion which is there between the digits of the given number.

    Second Step: The second step is to put down, under the second and third numbers, just two times of second and third number. Then add up the two rows.

    Finding the cube of 12

    Or, 123 = ?

    First Step: Digit in ten’s place is 1, so we write the cube of 1. And also as the ratio between 1 and 2 is 1:2, the next digits will be double the previous one. So, the first row is

    1 2 4 8

    Step II: In the above row our 2nd and 3rd digits (from right) are 4 and 2 respectively. So, we write down 8 and 4 below 4 and 2 respectively. Then add up the two rows.

    quickermaths

    Ex 2: 163 = ?

    Soln:

    quickermaths

    Explanations: 13 (from 16) = 1. So, 1 is our first digit in the first row. Digits of 16 are in the ratio 1:6, hence our other digits should be 1×6 = 6, 6×6 = 36, 36×6 = 216. In the second row, double the 2nd and 3rd number is written. In the third row, we have to write down only one digit below each column (except under the last column which may have more than one digit). So, after putting down the unit-digit, we carry over the rest to add up with the left-hand column. Here,

    i) Write down 6 of 216 and carry over 21.

    ii) 36 + 72 + 21 (carried) = 129, write down 9 and carry over 12.

    iii) 6 + 12 + 12 (carried) = 30, write down 0 and carry over 3.

    iv) 1 + 3 (carried) = 4, write down 4.

    Popularity: 54%

    Filed under: Speedy Calculation, Vedic Mathematics 20 Comments
    19Oct/090

    Vedic Multiplication by 9, 99, 999 and so on

    When any number has to be multiplied by a series of 9s, like 9, 99, 999, 9999 and so on than we can apply this very simple vedic maths technique to increase your speed of calculation.

    Multiplication with 9/ 99 / 999 and so on.

    we know, 789 × 999 = 788,211

    You will get the answers in two parts,

    • The left hand side of the answer: subtract 1 from 789, which is 788
    • The right hand side of the answer subtract 789 from 1000 = 1000-789= 211

    Thus, 999 x 789 = 789-1   |  1000-789 = 788, 211 (answer)

    {for the right hand side of the answer, 789 should be subtracted from (999+1)}

    or,  99999 x 78 = 78-1   | 100000 - 78

    = 7799922

    {78 should be subtracted from (99999+1)}

    Another example:

    1203579 × 9999999 = 1203579-1   | 10000000- 1203579

    =120357887964 21

    Number in red is 1 less than 1203579. Number in blue is (10000000-1203579). Hence the answer.

    This method has to be altered a little bit when number of 9s are lessers than the number of digit in the divisor.

    1432  x 9 = 1432 (10 – 1) = 14320 – 1432 = 12888

    So for multiplication with 9, put a zero after that number and subtract the number itself from that.

    Likewise for 99 put two zeroes after that number .

    3256 x 99 = 325600 – 3256 =  322344

    Popularity: 23%

    Filed under: Speedy Calculation, Vedic Mathematics No Comments
    3Oct/093

    A census taker approaches a house

    A census taker approaches a house and asks the woman who answers the door, “How many children do you have, and what are their ages?”

    Woman: "I have three children, the product of their ages are 36, the sum of their ages are equal to the address of the house next door."

    The census taker walks next door, comes back and says "I need more information."

    The woman replies "I have to go, my oldest child is sleeping upstairs."

    Census taker: "Thank you, I now have everything I need."

    What are the ages of each of the three children?

    Popularity: 2%

    Filed under: Puzzles 3 Comments
    23Sep/094

    The Great Pizza Deal

    The 10" pizza sells for $ 3.99 at my favorite pizza store. The store claims they have a great deal on the large 12" pizza, which is specially priced at $ 4.88. What is the per cent discount the store is offering?

    Leave your answer below:

    Popularity: 3%

    Filed under: Puzzles 4 Comments
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