Comments on: The Criss-Cross Method: An Alternative Form of Multiplication http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/ Vedic Maths Tricks | Puzzles, Brainteasers & Riddles Fri, 24 May 2013 09:10:56 +0000 hourly 1 http://wordpress.org/?v=3.1.4 By: flamefletcher http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/comment-page-1/#comment-14656 flamefletcher Thu, 05 Jul 2012 13:19:19 +0000 http://www.quickermaths.com/?p=2732#comment-14656 And for a right angled triangle. This is the formula. A,B,C are Vertices AC is hypotenuse. 90/(AB+BC)=P And then multiply P with other sides except the hypotenuse And for a right angled triangle.
This is the formula.
A,B,C are Vertices
AC is hypotenuse.

90/(AB+BC)=P
And then multiply P with other sides except the hypotenuse

]]> By: flamefletcher http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/comment-page-1/#comment-14655 flamefletcher Thu, 05 Jul 2012 13:17:26 +0000 http://www.quickermaths.com/?p=2732#comment-14655 To find out the angles of an Obtuse angled triangle and other side. Use the Parallelogram law of vectors in Physics. Google it and you will find the formula. To find out the angles of an Obtuse angled triangle and other side.
Use the Parallelogram law of vectors in Physics.
Google it and you will find the formula.

]]> By: flamefletcher http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/comment-page-1/#comment-14654 flamefletcher Thu, 05 Jul 2012 13:15:06 +0000 http://www.quickermaths.com/?p=2732#comment-14654 yeah surya you are right. I found out now that my theory is only true for Acute angled triangles. Not for right angled traingles and for obtuse triangles. The example i took below is an obtuse angled triangle. You can test it with any acute angled triangle and tell me the result and if you can .... prove thats also wrong. yeah surya you are right.
I found out now that my theory is only true for Acute angled triangles.
Not for right angled traingles and for obtuse triangles.
The example i took below is an obtuse angled triangle.
You can test it with any acute angled triangle and tell me the result and if you can …. prove thats also wrong.

]]> By: surya http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/comment-page-1/#comment-14609 surya Tue, 03 Jul 2012 01:29:26 +0000 http://www.quickermaths.com/?p=2732#comment-14609 sorry i was referring to the flamefletcher method to find angles given the sides of a triangle. sorry i was referring to the flamefletcher method to find angles given the sides of a triangle.

]]> By: surya http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/comment-page-1/#comment-14607 surya Mon, 02 Jul 2012 16:21:00 +0000 http://www.quickermaths.com/?p=2732#comment-14607 The first comment i guess is not correct relating to finding the angles of the triangle given the sides of the triangle. the example given is also absurd where 2 6 10 will not form a triangle as(2+6<10 which cant be a triangle) also one can cross check for 3 4 5 sides of a right triangle where the given formula does not give right angle to any angle of the triangle. Correct me if i am wrong. The first comment i guess is not correct relating to finding the angles of the triangle given the sides of the triangle. the example given is also absurd where 2 6 10 will not form a triangle as(2+6<10 which cant be a triangle) also one can cross check for 3 4 5 sides of a right triangle where the given formula does not give right angle to any angle of the triangle. Correct me if i am wrong.

]]> By: FlameFletcher http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/comment-page-1/#comment-14504 FlameFletcher Wed, 27 Jun 2012 14:14:25 +0000 http://www.quickermaths.com/?p=2732#comment-14504 Ok well let me submit something. I hope you will like it vineet. In a triangle. we know the relation ship between sides and angles with trignometry. but how can we find out angles if we know the sides in a simple method? use '&' as the proportionality symbol. in a triangle ABC the side opposite to angleA is BC , side opposite to angleC is AB etc. so as the side AB increases then angleC definitely increases. right? so AngleA & BC (& ---> means directly proportional to) AngleB & AC AngleC & AB Let 'P' be a constant. AngleA = P(BC) -----> 1 AngleB = P(AC) ------>2 AngleC = P(AB) ------>3 Adding 1,2,3 we get...... AngleA+AngleB+AngleC = P(BC+AC+AB) But AngleA+AngleB+AngleC = 180 therefore, 180= P(BC+AC+AB) => P= 180/(BC+AC+AB) from formula if we know the 3 sides of a triangle we can find the constant 'P'. and to get an angle. AngleA = P(BC) so multiply P with a side opposite to the angle to get that angle. here is an Example sum. 2,6,10 are the 3 sides of a triangle. Find out all their angles. From my formula above, P = 180/(AB+BC+CA) AB+BC+CA = 2+6+10 = 18 => P=180/18 =10 therefore P=10 degrees per unit distance. that means if there is an increase of 1 unit distance then the angle opposite to that side increases by 10 degrees. AngleA = 10(BC) = 10(2) = 20 degrees AngleB = 10(CA) = 10(6) = 60 degrees AngleC = 10(AB) = 10(10)=100 Degrees Therefore the angles are found. Note: This formula can be used for any type of triangle and this formula is 100% usable and proved. Note:The value of P is different for different triangles. So we always have to find P before finding angles. Feel Free to use it and please publish this on this site. Ok well let me submit something.
I hope you will like it vineet.
In a triangle.
we know the relation ship between sides and angles with trignometry.
but how can we find out angles if we know the sides in a simple method?
use ‘&’ as the proportionality symbol.
in a triangle ABC the side opposite to angleA is BC , side opposite to angleC is AB etc.
so as the side AB increases then angleC definitely increases. right?
so
AngleA & BC (& —> means directly proportional to)
AngleB & AC
AngleC & AB

Let ‘P’ be a constant.

AngleA = P(BC) —–> 1
AngleB = P(AC) ——>2
AngleC = P(AB) ——>3

Adding 1,2,3 we get……
AngleA+AngleB+AngleC = P(BC+AC+AB)

But AngleA+AngleB+AngleC = 180

therefore, 180= P(BC+AC+AB)

=> P= 180/(BC+AC+AB)

from formula if we know the 3 sides of a triangle we can find the constant ‘P’.
and to get an angle.
AngleA = P(BC)
so multiply P with a side opposite to the angle to get that angle.

here is an Example sum.

2,6,10 are the 3 sides of a triangle. Find out all their angles.

From my formula above, P = 180/(AB+BC+CA)
AB+BC+CA = 2+6+10 = 18

=> P=180/18
=10

therefore P=10 degrees per unit distance.
that means if there is an increase of 1 unit distance then the angle opposite to that side increases by 10 degrees.

AngleA = 10(BC) = 10(2) = 20 degrees
AngleB = 10(CA) = 10(6) = 60 degrees
AngleC = 10(AB) = 10(10)=100 Degrees

Therefore the angles are found.

Note: This formula can be used for any type of triangle and this formula is 100% usable and proved.

Note:The value of P is different for different triangles. So we always have to find P before finding angles.
Feel Free to use it and please publish this on this site.

]]> By: Vilas Thakur http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/comment-page-1/#comment-14268 Vilas Thakur Mon, 11 Jun 2012 13:38:46 +0000 http://www.quickermaths.com/?p=2732#comment-14268 Hello , thanks admin for writing so many methods , tricks , techniques for solving Additions ,Subtractions , Multiplications & Divisions in Quicker math”s ! Interested students are requested to Learn one by one to know Basic Math’s & Vedic Maths !! I am also one of the Tutor to teach Basic Math’s & Vedic Maths as Home Tuition Classes & through Mail id for Outstation Students .To know more details please do write on my mail id is basic.maths483@gmail.com thanks once again Quicker Math’s * I have passed M.Sc. ( STAT ) in Ist class from Nagpur University in 1981 . Hello , thanks admin for writing so many methods , tricks , techniques for solving Additions ,Subtractions , Multiplications & Divisions in Quicker math”s ! Interested students are requested to Learn one by one to know Basic Math’s & Vedic Maths !! I am also one of the Tutor to teach Basic Math’s & Vedic Maths as Home Tuition Classes & through Mail id for Outstation Students .To know more details please do write on my mail id is basic.maths483@gmail.com thanks once again Quicker Math’s * I have passed M.Sc. ( STAT ) in Ist class from Nagpur University in 1981 .

]]> By: MARS http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/comment-page-1/#comment-13584 MARS Wed, 02 May 2012 03:29:00 +0000 http://www.quickermaths.com/?p=2732#comment-13584 Good working. But its some what confuse & difficult to understand at a glance. Good working. But its some what confuse & difficult to understand at a glance.

]]> By: Vedic Maths Course http://www.quickermaths.com/the-criss-cross-method-an-alternative-form-of-multiplication/comment-page-1/#comment-13570 Vedic Maths Course Mon, 30 Apr 2012 17:04:25 +0000 http://www.quickermaths.com/?p=2732#comment-13570 [...] Vertically and crosswise multiplications - criss-cross method [...] [...] Vertically and crosswise multiplications – criss-cross method [...]

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