Who is behind QuickerMaths?
I am Vineet Patawari - PGDM (IIM Indore), ACA, B.Com(H). My passion for Mathematics, specially Vedic Maths encouraged me to start QuickerMaths
I believe that if trained properly using powerful tools like Vedic Maths, the immense intellect of human mind can be ignited instantly - find out more
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September 19th, 2010 - 04:14
Ans: 2 Threads.
Steps:
a) Burn thread 1 at one end and at the same time burn thread 2 at both the ends.
b) When thread 2 burns out completly it is half an hour, and thread 1 will take another half an hour to burn out.
c) At this half an hour, burn the other end of thread 1 as well and it will take 15 mins to burn out completely.
Total time taken: 30 mins (thread 2) + 15 mins (2nd phase of thread 1) = 45 mins
September 19th, 2010 - 04:12
Ans: 2 Threads.
Steps:
a) Burn thread 1 at one end and at the same time burn thread 2 at both the ends.
b) When thread 2 burns out completly it is half an hour, and thread 1 will take another half an hour to burn out.
c) At this half an hour, burn the other end of thread 1 as well and it will take 15 mins to burn out completely.
Total time taken: 30 mins (thread 1) + 15 mins (2nd phase of thread 2)
September 11th, 2010 - 10:05
only 1 thread is required
lighten one end of the thread till it burns half which takes 15 min
and the remainning half takes 45 min so it can be measured directly
September 11th, 2010 - 09:39
i have a different solution burn 1 thread from both the ends and the 2 thread at 4 places since the whole thread takes 1hr to burn completely the time in which individual pieces burn till completion is 15min (30+15)min
September 9th, 2010 - 18:27
Firstly there are eleven threads in the picture.
Answer to the riddle:
Only one thread is required…
a. burn the thread from one side
b.After 30 min the thread would have burned half.
c.now, burn the thread from the other end also.
d.after 15 min. the complete thread is burned.
so, (30+15) min.=45 min.
September 9th, 2010 - 19:25
Thanks Govind for pointing out about 11 threads in the picture. Though the pic has nothing to do with the question.
Your answer is not completely correct. Think about it
Keep commenting!!
-Vineet
September 11th, 2010 - 09:42
the threads burn unevenly isinted so how come this is correct
September 9th, 2010 - 11:17
min.’m 2 threads r required…
1. burn both d threads( one from both d ends & d other from just 1 end)
2.After 30 min., first thread would have burned completely and other would require another 30 min. to burn completely.
3.after 15 min. d second one will also gt burned.
so, (30+15) min.=45 min.
September 9th, 2010 - 11:19
min.’m 2 threads r required…
1. burn both d threads( one from both d ends & d other from just 1 end)
2.After 30 min., first thread would have burned completely and other would require another 30 min. to burn completely.
3.now, burn d second thread from d other end also.
3.after 15 min. d second one will also gt burned.
so, (30+15) min.=45 min.
September 8th, 2010 - 22:55
Sounds like the waterjug problem we had in AI.
September 8th, 2010 - 15:58
2 Threads:
Burn Thread 1 from both ends: Time taken will be 30 Min
The, Burn thread 2 from both ends and centre: Time taken to burn is 15 Min
Total 45 Min