# You can make a difference

I remember back to early 2005 (before going for my post graduation), when I’d just started preparing for some competitive examination, that even though I had great ambitions, my knowledge, expertise, and confidence as a student was sorely lacking. My love for internet (as a source of information) made me stumble through various places on the web to know maths short cuts and quick maths tricks, but without much to gain from it.

Now, after having being there and facing it all as a student first and then as a facilitator (though I take good number of Quants classes for CAT aspirants, I would not liked to be called a tutor or a teacher. These titles should be reserved for people of great wisdom and learning) for over 4-5 years I felt I had a really good grip on things; and even then, there were many things I am still struggling with.

Now at **QuickerMaths.com/Questions**, I’ve created a platform which is easily accessible to the students. Here they can get what they are looking for; at least things related to Quantitative Aptitude, Logical Reasoning, Analytical Reasoning and Critical Reasoning, Data Interprepatation – a platform where you can ask questions and where you can give answers.

**Let The Process Begin**

I’m starting the process by posting below an interesting formula of the topic- time and work . The aim is to initiate the process of collaborative learning. So anyone who wants to make a difference can post a comment with any explanation, formula, shortcut, trick, solved examples, etc. on the same topic (Time and Work for this post). If you’ve any question related to any topic in maths you can post it on the question-answer platform on this site.

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**Time and Work Formula**

I think the single most useful formula for the topic Time and Work is

N_{1}H_{1}D_{1}E_{1}W_{2 }= N_{2}H_{2}D_{2}E_{2}W_{1}

Where:

N_{1} and N_{2} = number of person

H_{1} and H_{2} = Hours worked by per person per day (assumed constant)

D_{1} and D_{2} = days

E_{1} and E_{2} = Efficiency

W_{1} and W_{2}= Amount of work done

Consider this example to understand the applicability of this formula –

A piece of work can be done by 16 men in 8 days working 12 hours a day.How many men are needed to complete another work, which is three times the first one,in 24 days working 8 hours a day. The efficiency of the second group is half that of the first group?

Solution –

N_{1}H_{1}D_{1}E_{1}W_{2 }= N_{2}H_{2}D_{2}E_{2}W_{1}

16*12*8*1*3 = N_{2}*8*24*0.5*1

N_{2} = (16*12*8*1*3)/ (8*24*0.5*1) = 48

So number of men required is 48.

Note – you can remove anything from formula is not given in the question. For example if the question would have been –

“A piece of work can be done by 16 men in 8 days working 12 hours a day.How many men are needed to complete another work, which is three times the first one,in 24 days working 8 hours a day.”

The applicable formula would have been –

N_{1}H_{1}D_{1}W_{2 }= N_{2}H_{2}D_{2}W_{1}

Since nothing is mentioned about efficiency, we remove it from both sides.

GOOD

THAT’S GOOD

Thanks for the auspicious writeup. It if truth be told

used to be a enjoyment account it. Look complicated to far added agreeable

from you! However, how could we keep in touch?

1 day

if the a+b do work in 10 days. b+c do work in 15 days. a+c do work in 12 days. then b independently do the work in how many days. solve it

24 days