One of our regular visitor Aisharya Rana contributed this puzzle, which I found interesting. Hence I’m posting here to be pondered upon by all. Post your answers as comments below –

**Arithmetic Puzzle**

In this puzzle you need to insert any arithmetic sign in between the same digit (from 1 to 9) repeated thrice. The final result should be 6 in each case. I’m doing one for illustration –

2 2 2 = 6

can be expressed as –

2 + 2 + 2 = 6

Solve the following yourself –

1 1 1 = 6

2 2 2 = 6

3 3 3 = 6

4 4 4 = 6

5 5 5 = 6

6 6 6 = 6

7 7 7 = 6

8 8 8 = 6

9 9 9 = 6

Remember, each equation can be solved in more than one way. Post your answers in the comment section below.

8^(1/3)+8^(1/3)+8^(1/3) = 6

(1+1+1)!=6

Every puzzle has been solved except first one so I am posting that solution:

(1+1+1)!=6

2+2+2=6

3*3-3=6

4+4-√4=6

5÷5+5=6

6÷6*6=6

7-7÷7=6

8-8^0-8^0=6

√9*√9-√9=6

2+2+2=6

3*3-3=6

4+4-√4=6

5÷5+5=6

6÷6*6=6

7-7÷7=6

8-8^0-8^0=6

√9*√9-√9=6

2+2+2=6

3*3-3=6

4+4-√4=6

5÷5+5=6

6÷6*6=6

7-7÷7=6

8-8^0-8^0=6

√9*√9-√9=6

3×3-3 = 6

6+6-6 = 6

Other you please solve.

3×3-3 = 6

6+6-6 = 6

Other you please solve.