**Speed Vedic Multiplication Trick**

**Vedic Multiplication by 11**

Step 1.

Assume that there are two invisible 0 (zeroes), one in front and one behind the number to be multiplied with 11

say if the number is **234, assume it to be 0 2 3 4 0**

Step 2.

Start from the right, add the two adjacent digits and keep on moving left

02340

Add the last zero to the digit in the ones column (4), and write the answer below the ones column. Then add 4 with digit on the left i.e. 3. Next add 3 with 2. Next 2 with 0.

0+4 = 4

4+3 = 7

3+2 = 5

2+0 = 2

So answer is 2574

Similarly,

36 x 11 = 0+3 | 3+6 | 6+0 = 396

74 x 11 =0+ 7 | 7+4 | 4+0 = 7 | _{1}1 | 4 = 814 (1 of 11 is carried over and added to next digit, so 7+1 = 8 )

6349 x 11 = (0+6) | (6+3) | (3+4) | (**4+9**) | 9+0 = 69839

This method works for all the number, no matter how long or short, times 11. Just try it yourself and get amazed at the simplicity of the concept.

In the next post will learn Vedic Multilplication by 111, 1111, 11111, and so on.

hey, doing good.

But what if the addition is 10 or above?

e.g. 567

Hi everyone, it’s my first go to see at this website,

and article is actually fruitful in favor of me, keep up posting these articles or reviews.

thank u.

Hi,

plz send me multiplication of 22,33etc on my email adress. I wil be very thankful to youuu,..

Firstly, Dipali, let me tell you that yours email address is not visible to me as a visitor of the blog only owner can see it, secondly I will be sharing here only so that most of the people can benefit from it and thirdly please subscribe to the entry which you post in this forum so that any response notification will reach you promptly.

First of all let me apologize to you and Vineet that I was trying to write how to multiply quicker by 12 and 13 and mistook that and has written those as 22 and 33………but since you have shown your concern to find out how to quickly multiply by 22 & 33….lets find an way……..this may sound silly and please keep in mind that necessity is the mother of all invention………..u can’t just mug-up all quicker techniques just try urself how to get a quicker method….ok pls dont mind if my sayings sounds like preaching………….ignore these all………

Lets take Vineet’s example: 234, assume it to be 0 2 3 4 0 now let us first multiply it by 11 as already shared by Vineet: (0+2)(2+3)(3+4)(4+0)

= 2574

so simple……now just twice it to get the multiplication by 22:> 2*2574=5148 is not this simple………………ha ha ha as 22 is nothing but 2*11….hope you will not ask now how to multiply by 33.

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Now coming to the point quick multiplication by 12 & 13:

let us take a big number say 6893 *12

= [just twice the number and add to the neighbour (this is actually an extension of the method as shared by Vineet)]

=(0+6)(12+8)(16+9)(18+3)(6+0)

=(0+6)2(0)2(5)2(1)(6+0) (The number outside bracket is nothing but carried nos.)

=82716 answer……………..please write-back if anybody feels any doubt ….actually by just simple 1-2 times practice this can be done orally.

Thanks Anupam for your efforts to explain the multiplication of 12 and 13. It will be useful for all.

If someone is need of the quick multiplication of 22, 33 etc please let me know which is an extension of the method shared by Vineet.

Sorry…..please see the above reply of mine to Dipali’s post.