Comments on: Weight Puzzles

By: Darliane

Darliane — Tue, 27 Jul 2010 19:33:17 +0000

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By: LAY ADALJA

LAY ADALJA — Wed, 26 May 2010 18:23:40 +0000

1.first take 3 and 3 balls.If they don’t weigh equal then the defective ball is here in this bunch.if they weigh equal then defective ball is in the set of other 6 balls.Thus we have 6 balls in which we need to find out the defective one.

2.now the bunch of other six balls are equal weighted..take 3 balls of from them and weigh them with the bunch of 3 balls of the above weighted..if they are equal then defective ball is in the other bunch of 3 balls and if they are not equal defective ball is in this 3 ball set.(if this set weighs heavier than the ideal group of 3 balls {that we have selected from the remaining set of 6 balls} than defective ball is heavier and vice versa..)

3.now we have 3 balls..take any 2 and weigh them with the other equal set of 2 balls..if they weigh equal then the remaining ball is defective..and if they don’t weigh equal then the ball which is heavier(as we have assumed the set if 3 is heavier than ideal set in the second step.) is defective in the scale..

By: divya

divya — Wed, 24 Feb 2010 07:12:14 +0000

for the first puzzle:12 balls
divide the balls into 2 patrs(6)(6)
place tem in two panels next..the one which is weighing heavier take dat and divide dose in into 2 equal parts (3)(3)
nw repaet the same ting .nw which is weighing heavier take dose 3 balls and now
dis is d 3rd measurment:
nw palce 1_1 in each panel
nw if dey are equal den d left is d ball we r searching for..else any of dose 2..

By: Mohit

Mohit — Thu, 04 Feb 2010 07:28:46 +0000

2.) 5 weights are required: 1,3,9,27 and 81

By: Hitesh Jain

Hitesh Jain — Wed, 03 Feb 2010 11:47:16 +0000

7 weights are required for measuring upto 120kgs.
1,2,4,8,16,32,64

By: Hitesh Jain

Hitesh Jain — Wed, 03 Feb 2010 11:44:38 +0000

divide 12 into 3 groups of 4 each
put 4balls on each side
1st if both equal then keep 2balls one side out of these 8 balls and 2 balls from remaining 4 balls.
If both equal then put 1 ball from these 4balls and 1 ball from remaining 2balls.if both equal then remaining ball will b defective.If both are not equal then ball kept from remaining 2 will b defective.
If group of 4 balls kept is not equal then leave 3rd group and take any 1 group from these 2 and keep 2balls on each side if both equal then defective will b from 2nd group remaining .

By: WINX

WINX — Wed, 03 Feb 2010 06:35:48 +0000

if the condition is that we can weigh each ball three times then:-

1)divide the balls in 6-6 and wieigh
2)one with bigger wgt is taken and divided into 3-3
3)if one is bigger and other is smaller then take the bigger 3 balls chunk and weigh 1-1 …if both are equal the left one is biiger one and the defctv one AND if one is bigger than the othr than the bigger one is defective and bigger.
4)but if on 3-3 weighng the balance show that they are equal then take the smaller 6 chunk as was in step 1 and then divide it into 3-3 ..weigh them ……choose the smaller 3 chunk and weigh 1-1….if equal then the left one i s smaaler and defctv …if one is gr8ter than other then smaler one is smaller and defctv:)

BUT IF CONDITION IS TO USE THE BALANCE ONLY THRICE THEN LOOK 4 OTHER ANS